136.271
Midterm Exam 2
November 17 2000
(50 minutes; justify your answers unless otherwise stated; no calculators)
1.[5] Find the radius of 
  convergence and the interval of convergence of the series 	
	
Use the ration test:
	
	The series converges if 
<1, 
      which means that 
, which in turn 
      gives 
 and so 
. 
      We see that the radius of convergence is 1/2. We now look at the edges of 
      the interval of convergence: 
	(a) 
. The series in this case 
  is (after a bit of cancellation) 
 which 
  converges (alternating series test).
	(b) 
. In this case the series 
  is 
. It diverges
So, the interval of convergence is [2.5,3.5).
2.[5]	Find a power series representation for the function 
.
	First we find a power series representation for 
. 
  We have 	
.
The series converges for 
, i.e., 
      for 
. So, in that interval we 
      have ![]()
	and so 
.
[Alternatively, since 
we 
      have 
 and so 
.]
3.[5] Find the sum of the series 
.
.
4.[5] Find the Maclaurin series representation for the function 
. 
  Show that 	
 is equal to its Maclaurin 
  series representation.
	![]()
	![]()
	![]()
	So, 
 (with 
) 
      and so 
 is the Maclaurin series 
      representation 	for the function 
. 
      To show that 
 we need to show 
      that the remainder 
 tends to 
      0 as 
 (with X between 0 	and 
      x). We have 
 and, as we have 
      seen it many times, the last limit is 0.
3.[5] Use binomial series to expand 
 
  as a power series and then find the 	sum 
.

	To get the sum 
 notice that this 
  series is what we get above for 
. 
  So, 	
.